Answer
$-1(2y+3)(y+1)$.
Work Step by Step
The given polynomial is
$=-2y^2-5y-3$
Factor out $-1$.
$=-1(2y^2+5y+3)$
Rewrite $5y$ as $3y+2y$.
$=-1(2y^2+3y+2y+3)$
Group the terms.
$=-1[(2y^2+3y)+(2y+3)]$
Factor each group.
$=-1[y(2y+3)+1(2y+3)]$
Factor out $(2y+3)$.
$=-1(2y+3)(y+1)$
Hence, the factor of the polynomial is $-1(2y+3)(y+1)$.
