Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.6 - Factoring ax^2 + bx + c = 0 - Monitoring Progress - Page 393: 6

Answer

$(2x+3)(3x-4)$.

Work Step by Step

The given polynomial is $=6x^2+x-12$ Rewrite $x$ as $9x-8x$. $=6x^2+9x-8x-12$ Group the terms. $=(6x^2+9x)+(-8x-12)$ Factor each group. $=3x(2x+3)-4(2x+3)$ Factor out $(2x+3)$. $=(2x+3)(3x-4)$ Hence, the factor of the polynomial is $(2x+3)(3x-4)$.
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