Answer
$(x-4)(3x-2)$.
Work Step by Step
The given polynomial is
$=3x^2-14x+8$
Rewrite $-14x$ as $-12x-2x$.
$=3x^2-12x-2x+8$
Group the terms.
$=(3x^2-12x)+(-2x+8)$
Factor each group.
$=3x(x-4)-2(x-4)$
Factor out $(x-4)$.
$=(x-4)(3x-2)$
Hence, the factor of the polynomial is $(x-4)(3x-2)$.
