Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.6 - Factoring ax^2 + bx + c = 0 - Monitoring Progress - Page 393: 1

Answer

$8(x-1)(x-6)$.

Work Step by Step

The given polynomial is $=8x^2-56x+48$ Factor out $8$. $=8(x^2-7x+6)$ Rewrite $-7x$ as $-6x-x$. $=8(x^2-6x-x+6)$ Group the terms. $=8[(x^2-6x)+(-x+6)]$ Factor each group. $=8[x(x-6)-1(x-6)]$ Factor out $(x-6)$. $=8(x-6)(x-1)$ Hence, the factor of the polynomial is $8(x-1)(x-6)$.
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