Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.4 - Solving Polynomial Equations in Factored Form - Exercises - Page 381: 8

Answer

$y=-2$ and $y=6$.

Work Step by Step

The given equation is $\Rightarrow (y+2)(y-6)=0$ Use zero-product property rule. $\Rightarrow y+2=0$ or $y-6=0$ Solve for $y$. $\Rightarrow y=-2$ or $y=6$ Check:- $y=-2$ $\Rightarrow (-2+2)(-2-6)=0$ $\Rightarrow 0(-8)=0$ $\Rightarrow 0=0$ True. Check:- $y=6$ $\Rightarrow (6+2)(6-6)=0$ $\Rightarrow 8(0)=0$ $\Rightarrow 0=0$ True. Hence, the solutions are $y=-2$ and $y=6$.
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