Answer
The solutions are $w=0$ and $w=6$.
Work Step by Step
Given: $w(w-6)^{2}=0$
$\implies w(w-6)(w-6)=0$
Using zero-product property, we have
$w=0$ or $w-6=0$
Solving for $w$, we obtain
$w=0$ or $w=6$.
The roots are $w=0$ and $w=6$.
Big Ideas Math - Algebra 1, A Common Core Curriculum
by Larson, Ron; Boswell, Laurie
Published by
Big Ideas Learning LLC
ISBN 10:
978-1-60840-838-2
ISBN 13:
978-1-60840-838-2
Chapter 7 - Polynomial Equations and Factoring - 7.4 - Solving Polynomial Equations in Factored Form - Exercises - Page 381: 18
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