Chapter 7 - Polynomial Equations and Factoring - 7.4 - Solving Polynomial Equations in Factored Form - Exercises - Page 381: 15

The solutions are $z=0$, $z=-2$ and $z=1$.

Given: $z(z+2)(z-1)=0$ Using zero-product property, we have $z=0$ or $z+2=0$ or $z-1=0$. Solving for $z$, we get $z=0$ or $z=-2$ or $z=1$. The roots are $z=0$, $z=-2$ and $z=1$.