Chapter 7 - Polynomial Equations and Factoring - 7.4 - Solving Polynomial Equations in Factored Form - Exercises - Page 381: 20

The roots are $n=2$ and $n=-9$.

Given: $(2-n)(6+\frac{2}{3}n)(n-2)=0$ Using zero-product property, we have $2-n=0$ or $6+\frac{2}{3}n=0$ or $n-2=0$ Solving for $n$, we get $n=2$ or $n=-9$ or $n=2$ The roots are $n=2$ and $n=-9$.