Chapter 7 - Polynomial Equations and Factoring - 7.4 - Solving Polynomial Equations in Factored Form - Exercises - Page 381: 37

The error in solving the equation was not considering the possibility of $6x$ being equal to zero. Given: $6x(x+5)=0$ Using zero-product property, we have $6x=0$ or $x+5=0$ Solving for $x$, we get $x=0$ or $x=-5$ The roots are $x=0$ and $x=-5$.

Given: $6x(x+5)=0$ Using zero-product property, we have $6x=0$ or $x+5=0$ The error in solving the equation was not considering the possibility of $6x$ being equal to zero. Solving for $x$, we get $x=0$ or $x=-5$ The roots are $x=0$ and $x=-5$.