Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.3 - Special Products of Polynomials - Exercises - Page 375: 8

Answer

$n^2+24n+144$.

Work Step by Step

The given expression is $=(-12-n)^2$ Factor out $-1$. $=(-1)^2(12+n)^2$ Simplify. $=(12+n)^2$ Use formula $(a+b)^2=a^2+2ab+b^2$. We have $a=12$ and $b=n$. $=(12)^2+2(12)(n)+(n)^2$ Simplify. $=144+24n+n^2$ Standard form. $=n^2+24n+144$ Hence, the product is $n^2+24n+144$.
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