Answer
$49n^{2}-70n+25$
Work Step by Step
$\text{Area}=(7n-5)^{2}$
Using square of a binomial pattern $(a-b)^{2}=a^{2}-2ab+b^{2}$, we have
$(7n-5)^{2}=(7n)^{2}-2(7n)(5)+5^{2}$
$=49n^{2}-70n+25$
Big Ideas Math - Algebra 1, A Common Core Curriculum
by Larson, Ron; Boswell, Laurie
Published by
Big Ideas Learning LLC
ISBN 10:
978-1-60840-838-2
ISBN 13:
978-1-60840-838-2
Chapter 7 - Polynomial Equations and Factoring - 7.3 - Special Products of Polynomials - Exercises - Page 375: 13
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