Answer
$x^{2}+8x+16$
Work Step by Step
$\text{Length of a side of the square}=x+4$
$\text{Area of the square}=(x+4)^{2}$
Using square of a binomial pattern $(a+b)^{2}=a^{2}+2ab+b^{2}$, we have
$(x+4)^{2}=x^{2}+2(x)(4)+4^{2}$
$=x^{2}+8x+16$