Answer
$\frac{1}{4}-c^2$.
Work Step by Step
The given expression is
$=(\frac{1}{2}-c)(\frac{1}{2}+c)$
Use sum and difference pattern $(a-b)(a+b)=a^2-b^2$.
We have $a=\frac{1}{2}$ and $b=c$.
$=(\frac{1}{2})^2-(c)^2$
Simplify.
$=\frac{1}{4}-c^2$
Hence, the product is $\frac{1}{4}-c^2$.
