Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.3 - Special Products of Polynomials - Exercises - Page 375: 24

Answer

$25g^2-4h^2$.

Work Step by Step

The given expression is $=(-5g-2h)(-5g+2h)$ Factor out $-1$. $=-1(5g+2h)(-5g+2h)$ Use distributive property. $=(5g+2h)(5g-2h)$ Use sum and difference pattern $(a+b)(a-b)=a^2-b^2$. We have $a=5g$ and $b=2h$. $=(5g)^2-(2h)^2$ Simplify. $=25g^2-4h^2$ Hence, the product is $25g^2-4h^2$.
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