Answer
$cos~6x+cos~2x=2~cos~4x~cos~2x$
Work Step by Step
$cos~6x+cos~2x=2~cos(\frac{6x+2x}{2})~cos(\frac{6x-2x}{2})=2~cos~4x~cos~2x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.5 - Multiple-Angle and Product-to-Sum Formulas - 7.5 Exercises - Page 548: 55
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