Answer
$sin~3θ+sin~θ=2~sin~2θ~cos~θ$
Work Step by Step
$sin~3θ+sin~θ=2~sin(\frac{3θ+θ}{2})~cos(\frac{3θ-θ}{2})=2~sin~2θ~cos~θ$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.5 - Multiple-Angle and Product-to-Sum Formulas - 7.5 Exercises - Page 548: 54
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