Answer
$2~tan^2u$
Work Step by Step
$\frac{1-cos~2u}{1+cos~2u}=\frac{1-(cos^2u-sin^2u)}{1+cos^2u-sin^2u}=\frac{1-cos^2u+sin^2u}{1-sin^2u+cos^2u}=\frac{sin^2u+sin^2u}{cos^2u+cos^2u}=\frac{2~sin^2u}{2~cos^2u}=2~tan^2u$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.5 - Multiple-Angle and Product-to-Sum Formulas - 7.5 Exercises - Page 548: 4
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