Answer
$sin(x+y)~cos(x-y)=\frac{1}{2}(sin~2x+sin~2y)$
Work Step by Step
$sin(x+y)~cos(x-y)=\frac{1}{2}[sin(x+y+x-y)+sin(x+y-(x-y))]=\frac{1}{2}(sin~2x+sin~2y)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.5 - Multiple-Angle and Product-to-Sum Formulas - 7.5 Exercises - Page 548: 52
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