Answer
The identity is verified.
The graph of $f(y)=cot^2y(sec^2y-1)$
Work Step by Step
$1+tan^2y=sec^2y$
$tan^2y=sec^2y-1$
$cot^2y(sec^2y-1)=cot^2y~tan^2y=\frac{1}{tan^2y}·tan^2y=1$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.2 - Verifying Trigonometric Identities - 7.2 Exercises - Page 520: 26
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