Answer
The identity is verified.
$\frac{1}{tan~x}+\frac{1}{cot~x}=cot~x+tan~x$
Work Step by Step
$\frac{1}{tan~x}+\frac{1}{cot~x}=\frac{1}{\frac{1}{cot~x}}+\frac{1}{\frac{1}{tan~x}}=cot~x+tan~x$
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