Answer
The identity is verified.
$\frac{1}{sin~x}-\frac{1}{csc~x}=csc~x-sin~x$
Work Step by Step
$\frac{1}{sin~x}-\frac{1}{csc~x}=csc~x-\frac{1}{\frac{1}{sin~x}}=csc~x-sin~x$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.2 - Verifying Trigonometric Identities - 7.2 Exercises - Page 520: 20
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