Answer
The trigonometric Identity is verified.
$cos^2β-sin^2β=2~cos^2β-1$
Work Step by Step
$sin^2β+cos^2β=1~~$ (Pythagoren Identity)
$cos^2β-1=-sin^2β$
Now:
$cos^2β-sin^2β=cos^2β+cos^2β-1=2~cos^2β-1$
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