Answer
$arccos(-\frac{\sqrt 2}{2})=\frac{3\pi}{4}$
Work Step by Step
The range of $arccos~x$ is $[0,\pi]$. So,
$arccos(-\frac{\sqrt 2}{2})=\frac{3\pi}{4}$, because $cos(\frac{3\pi}{4})=-\frac{\sqrt 2}{2}$ and $0\leq\frac{3\pi}{4}\leq\pi$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - Review Questions - Page 501: 93
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
