Answer
$arcsin(-1)=-\frac{\pi}{2}$
Work Step by Step
The range of $arcsin~x$ is $[-\frac{\pi}{2},\frac{\pi}{2}]$. So,
$arcsin(-1)=-\frac{\pi}{2}$ because $sin(-\frac{\pi}{2})=-1$ and $-\frac{\pi}{2}\leq-\frac{\pi}{2}\leq\frac{\pi}{2}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 6 - Review Questions - Page 501: 92
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