Answer
$sin(\frac{\pi}{3})=\frac{\sqrt 3}{2}$
$cos(\frac{\pi}{3})=\frac{1}{2}$
$tan(\frac{\pi}{3})=\sqrt 3$
Work Step by Step
Let $θ'$ be the reference angle. We must have that $0\leqθ'\lt2\pi$
But, since $0\leqθ=\frac{\pi}{3}\lt2\pi$, it is not necessary to find a reference angle.
$sin(\frac{\pi}{3})=\frac{\sqrt 3}{2}$
$cos(\frac{\pi}{3})=\frac{1}{2}$
$tan(\frac{\pi}{3})=\sqrt 3$
