Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - Review Questions - Page 501: 42

Answer

$sin~\theta=-\frac{24}{25}$ $cos~\theta=\frac{7}{25}$ $tan~\theta=-\frac{24}{7}$ $cot~\theta=-\frac{7}{24}$ $sec~\theta=\frac{25}{7}$ $csc~\theta=-\frac{25}{24}$

Work Step by Step

Distance from the origin to the given point: $d=\sqrt {7^2+(-24)^2}=\sqrt {625}=25$ $sin~\theta=\frac{opp}{hyp}=\frac{-24}{25}=-\frac{24}{25}$ $cos~\theta=\frac{adj}{hyp}=\frac{7}{25}$ $tan~\theta=\frac{opp}{adj}=\frac{-24}{7}=-\frac{24}{7}$ $cot~\theta=\frac{adj}{opp}=\frac{7}{-24}=-\frac{7}{24}$ $sec~\theta=\frac{hyp}{adj}=\frac{25}{7}$ $csc~\theta=\frac{hyp}{opp}=\frac{25}{-24}=-\frac{25}{24}$
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