Answer
According to the graph the x-intercepts are: $(6,0)$ and $(-\frac{5}{2},0)$
Work Step by Step
$f(x)=0$
$2x^2-7x-30=0~~$ ($a=2,b=-7,c=-30$):
$x=\frac{-(-7)±\sqrt {(-7)^2-4(2)(-30)}}{2(2)}=\frac{7±\sqrt {289}}{4}=\frac{7±17}{4}$
$x=6$ or $x=-\frac{10}{4}=-\frac{5}{2}$
x-intercepts: $(6,0)$ and $(-\frac{5}{2},0)$
