Answer
$y=-450(x-6)^2+6$
Work Step by Step
Vertex: $(h,k)=(6,6)$
Standard form:
$y=a(x−h)^2+k$
$y=a(x-6)^2+6$
Now, use the point $(\frac{61}{10},\frac{3}{2})$ to find $a$:
$\frac{3}{2}=a(\frac{61}{10}-6)^2+6$
$\frac{3}{2}-6=a(\frac{1}{10})^2$
$-\frac{9}{2}=a(\frac{1}{100})$
$a=-\frac{900}{2}=-450$
$y=-450(x-6)^2+6$
