Answer
$y=4(x-1)^2-2$
Work Step by Step
Vertex: $(h,k)=(1,-2)$
Standard form:
$y=a(x-h)^2+k$
$y=a(x-1)^2+(-2)$
$y=a(x-1)^2-2$
Now, use the point $(-1,14)$ to find $a$:
$14=a(-1-1)^2-2$
$14+2=a(4)$
$a=\frac{16}{4}=4$
$y=4(x-1)^2-2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 249: 39
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