Answer
According to the graph the x-intercepts are: $(3,0)$ and $(6,0)$
Work Step by Step
$f(x)=0$
$x^2-9x+18=0~~$ ($a=1,b=-9,c=18$):
$x=\frac{-(-9)±\sqrt {(-9)^2-4(1)(18)}}{2(1)}=\frac{9±\sqrt 9}{2}=\frac{9±3}{2}$
$x=6$ or $x=3$
x-intercepts: $(3,0)$ and $(6,0)$
