Answer
$y=(x+2)^2+5$
Work Step by Step
Vertex: $(h,k)=(-2,5)$
Standard form:
$y=a(x-h)^2+k$
$y=a[x-(-2)]^2+5$
$y=a(x+2)^2+5$
Now, use the point $(0,9)$ to find $a$:
$9=a(0+2)^2+5$
$9-5=a(4)$
$a=\frac{4}{4}=1$
$y=(x+2)^2+5$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 249: 37
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