Answer
$(g^{-1}~o~g^{-1})(-1)=-1$
Work Step by Step
$g(x)=x^3$
$y=x^3~~$ (Interchange $x$ and $y$):
$x=y^3$
$y=\sqrt[3] x$
$g^{-1}(x)=\sqrt[3] x$
$(g^{-1}~o~g^{-1})(-1)=g^{-1}(g^{-1}(-1))=g^{-1}(\sqrt[3] {-1})=g^{-1}(-1)=\sqrt[3] {-1}=-1$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 2 - 2.7 - Inverse Functions - 2.7 Exercises - Page 229: 82
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