Answer
$f^{-1} (x)=x+5$
Domain of the function $f$ is: $[5, \infty)$.
Domain of the inverse of function $f$ is: $[0, \infty)$.
Work Step by Step
We have $y=|x-5|=x-5$
or, $x=y-5$
or, $ y=x+5$
Replace $y$ with $f^{-1} (x)$.
so, $f^{-1} (x)=x+5$
