Answer
$S=2$
Work Step by Step
$\displaystyle \sum_{i=0}^{∞}(0.5)^i=(0.5)^0+(0.5)^1+(0.5)^2+...$
$a_1=(0.5)^0=1$
$r=\frac{a_2}{a_1}=\frac{(0.5)^1}{(0.5)^0}=0.5$
$S=\frac{a_1}{1-r}=\frac{1}{1-0.5}=\frac{1}{0.5}=2$
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