Answer
$S_5=23.056$
Work Step by Step
$\displaystyle \sum_{i=1}^{5}10(0.6)^{i-1}=10(0.6)^0+10(0.6)^1+10(0.6)^2+...+10(0.6)^5$
$a_1=10(0.6)^0=10$
$r=\frac{a_2}{a_1}=\frac{10(0.6)^1}{10(0.6)^0}=0.6$
$S_5=a_1(\frac{1-r^n}{1-r})=10(\frac{1-0.6^5}{1-0.6})=10~\frac{0.92224}{0.4}=23.056$
