Answer
$_5C_3=10$
Work Step by Step
$_nC_r=\frac{n!}{(n-r)!\times r!}$
$_5C_3=\frac{5!}{(5-3)!\times(3!)}=\frac{5\times4\times3!}{2!\times3!}=\frac{5\times4}{2}=\frac{20}{2}=10$
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