Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.5 - The Binomial Theorem - 11.5 Exercises - Page 813: 48

Answer

$a=-160$

Work Step by Step

According to the Binomial Theorem, the 4th, that is, the ($3+1$)th term of $(x-2)^6$ is: $_6C_3(x)^{6-3}(-2)^3=\frac{6!}{(6-3)!\times3!}x^3(-8)=(20)x^3(-8)=-160x^3$ $ax^3=-160x^3$ $a=-160$
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