Answer
$a=-160$
Work Step by Step
According to the Binomial Theorem, the 4th, that is, the ($3+1$)th term of $(x-2)^6$ is:
$_6C_3(x)^{6-3}(-2)^3=\frac{6!}{(6-3)!\times3!}x^3(-8)=(20)x^3(-8)=-160x^3$
$ax^3=-160x^3$
$a=-160$
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