Answer
$a=160$
Work Step by Step
According to the Binomial Theorem, the 4th, that is, the ($3+1$)th term of $(x+2)^6$ is:
$_6C_3(x)^{6-3}(2)^3=\frac{6!}{(6-3)!\times3!}x^3(8)=(20)x^3(8)=160x^3$
$ax^3=160x^3$
$a=160$
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