Answer
$(y-3)^3=y^3-9y^2+27y-27$
Work Step by Step
$(y-3)^3=~_3C_0y^3+~_3C_1y^2(-3)^1+~_3C_2y^1(-3)^2+~_3C_3(-3)^3=y^3+3y^2(-3)+3y(9)+(-27)=y^3-9y^2+27y-27$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.5 - The Binomial Theorem - 11.5 Exercises - Page 813: 19
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