Answer
$S=2$
Work Step by Step
$\displaystyle \sum_{n=0}^{∞}(\frac{1}{2})^n=(\frac{1}{2})^0+(\frac{1}{2})^1+(\frac{1}{2})^2+...$
$a_1=(\frac{1}{2})^0=1$
$r=\frac{a_2}{a_1}=\frac{(\frac{1}{2})^1}{(\frac{1}{2})^0}=\frac{1}{2}$
$S=\frac{a_1}{1-r}=\frac{1}{1-\frac{1}{2}}=2$