Answer
$32+24+18+13.5+10.125=\displaystyle \sum_{n=1}^{5}32(0.75)^{n-1}$
Work Step by Step
$10.125=32(0.75)^4$
$32+24+18+13.5+10.125=32(0.75)^0+32(0.75)^1+32(0.75)^2+32(0.75)^3+32(0.75)^4=\displaystyle \sum_{n=1}^{5}32(0.75)^{n-1}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 796: 68
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
