Answer
$10+30+90+...+7290=\displaystyle \sum_{n=1}^{7}10(3)^{n-1}$
Work Step by Step
$7290=10(729)=10(3)^6$
$10+30+90+...+7290=10(3)^0+10(3)^1+10(3)^2+...10(3)^6=\displaystyle \sum_{n=1}^{7}10(3)^{n-1}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.3 - Geometric Sequences and Series - 11.3 Exercises - Page 796: 65
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