Answer
$S_{100}=19200$
Work Step by Step
$d=-2-(-6)=2-(-2)=4$.
$a_n=a_1+(n-1)d$
$a_{100}=-6+(100-1)4$
$a_{100}=-6+99(4)$
$a_{100}=390$
$S_n=\frac{n}{2}(a_1+a_n)$
$S_{100}=\frac{100}{2}(-6+390)=50(384)=19200$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.2 - Arithmetic Sequences and Partial Sums - 11.2 Exercises - Page 786: 52
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