Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 777: 27

Answer

See the picture.

Work Step by Step

$a_n=\frac{2}{3}n$ $a_1=\frac{2}{3}(1)=\frac{2}{3}$ $a_2=\frac{2}{3}(2)=\frac{4}{3}$ $a_3=\frac{2}{3}(3)=\frac{6}{3}=2$ $a_4=\frac{2}{3}(4)=\frac{8}{3}$ $a_5=\frac{2}{3}(5)=\frac{10}{3}$ $a_6=\frac{2}{3}(6)=\frac{12}{3}=4$ $a_7=\frac{2}{3}(7)=\frac{14}{3}$ $a_8=\frac{2}{3}(8)=\frac{16}{3}$ $a_9=\frac{2}{3}(9)=\frac{18}{3}=6$ $a_{10}=\frac{2}{3}(10)=\frac{20}{3}$
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