Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 777: 24

Answer

$a_{16}=-240$

Work Step by Step

$a_n=(-1)^{n-1}[n(n-1)]$ $a_{16}=(-1)^{16-1}[16(16-1)]=(-1)^{15}[16(15)]=(-1)(240)=-240$
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