Answer
$a_{11}=\frac{44}{239}$
Work Step by Step
$a_n=\frac{4n}{2n^2-3}$
$a_{11}=\frac{4(11)}{2(11)^2-3}=\frac{44}{2(121)-3}=\frac{44}{242-3}=\frac{44}{239}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 777: 25
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