Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.1 - Sequences and Series - 11.1 Exercises - Page 777: 22

Answer

$a_1=\frac{1}{2}$ $a_2=-\frac{1}{5}$ $a_3=\frac{1}{10}$ $a_4=-\frac{1}{17}$ $a_5=\frac{1}{26}$

Work Step by Step

$a_n=\frac{(-1)^{n+1}}{n^2+1}$ $a_1=\frac{(-1)^{1+1}}{1^2+1}=\frac{(-1)^{2}}{1+1}=\frac{1}{2}$ $a_2=\frac{(-1)^{2+1}}{2^2+1}=\frac{(-1)^{3}}{4+1}=\frac{-1}{5}=-\frac{1}{5}$ $a_3=\frac{(-1)^{3+1}}{3^2+1}=\frac{(-1)^{4}}{9+1}=\frac{1}{10}$ $a_4=\frac{(-1)^{4+1}}{4^2+1}=\frac{(-1)^{5}}{16+1}=\frac{-1}{17}=-\frac{1}{17}$ $a_5=\frac{(-1)^{5+1}}{5^2+1}=\frac{(-1)^{6}}{25+1}=\frac{1}{26}$
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