Answer
Solutions:
$x=-\frac{1}{2}+\frac{\sqrt 6}{2}i$
$x=-\frac{1}{2}-\frac{\sqrt 6}{2}i$
Work Step by Step
$4x^2+4x+7=0~~$ ($a=4,b=4,c=7$):
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-4±\sqrt {4^2-4(4)(7)}}{2(4)}=\frac{-4±\sqrt {-96}}{8}=\frac{-4±4\sqrt 6i}{8}=-\frac{1}{2}±\frac{\sqrt 6}{2}i$
$x=-\frac{1}{2}+\frac{\sqrt 6}{2}i$ or $x=-\frac{1}{2}-\frac{\sqrt 6}{2}i$
