Answer
$\frac{4}{1-2i}=\frac{4}{5}+\frac{8}{5}i$
Work Step by Step
$\frac{4}{1-2i}=\frac{4}{1-2i}\frac{1+2i}{1+2i}=\frac{4(1+2i)}{(1-2i)(1+2i)}=\frac{4+8i}{1-4i^2}=\frac{4+8i}{1+4}=\frac{4}{5}+\frac{8}{5}i$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - Review Exercises - Page 153: 71
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