Answer
Solutions:
$x=\frac{1}{2}+\frac{\sqrt {249}}{6}$
$x=\frac{1}{2}-\frac{\sqrt {249}}{6}$
Work Step by Step
$-20-3x+3x^2=0~~$ ($a=3,b=-3,c=-20$):
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-(-3)±\sqrt {(-3)^2-4(3)(-20)}}{2(3)}=\frac{3±\sqrt {249}}{6}=\frac{1}{2}±\frac{\sqrt {249}}{6}$
